4q^2-33q-27=

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Solution for 4q^2-33q-27= equation:


Simplifying
4q2 + -33q + -27 = 0

Reorder the terms:
-27 + -33q + 4q2 = 0

Solving
-27 + -33q + 4q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(-3 + -4q)(9 + -1q) = 0

Subproblem 1

Set the factor '(-3 + -4q)' equal to zero and attempt to solve: Simplifying -3 + -4q = 0 Solving -3 + -4q = 0 Move all terms containing q to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -4q = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -4q = 0 + 3 -4q = 0 + 3 Combine like terms: 0 + 3 = 3 -4q = 3 Divide each side by '-4'. q = -0.75 Simplifying q = -0.75

Subproblem 2

Set the factor '(9 + -1q)' equal to zero and attempt to solve: Simplifying 9 + -1q = 0 Solving 9 + -1q = 0 Move all terms containing q to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -1q = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -1q = 0 + -9 -1q = 0 + -9 Combine like terms: 0 + -9 = -9 -1q = -9 Divide each side by '-1'. q = 9 Simplifying q = 9

Solution

q = {-0.75, 9}

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